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About 750 cal of heat is added to a system that does 42 J of work, what is the change in the system internal energy in calories?
Mga sagot sa #1 sa Tanong: About 750 cal of heat is added to a system that does 42 J of work, what is the change in the system internal energy in calories?
Given:
Q = 750 cal
W = 42 J = 10.0 cal (divide by 4.184)
Find:
ΔU = ?
Use the formula:
ΔU = Q – W
ΔU = (750 cal) – (10.0 cal)
ΔU = 740 cal
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